python实现的阳历转阴历（农历）算法
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这篇文章主要介绍了python实现的阳历转阴历（农历）算法,需要的朋友可以参考下
搜索了好几个python实现的万年历多有部分时间有问题，好多是来自这个代码：
代码如下:#!/usr/bin/env python# -*- coding: utf-8 -*-'''Usage:& ccal Month [4-Digit-Year]&& or:& ccal 4-Digit-Year Month
This Python script is to show Solar and Lunar calender at thesame time. You need to have Python (2.0 or above) installed.
Acceptable date range:& 1900/2 -- 2049/12
Output contains Chinese characters (mainland GB2312 encoding),must be viewed in a Chinese-enabled system or "cxterm" etc.programms under UNIX X-Windows.
The major reference for me to compose this program is:lunar-2.1.tgz (1992), composed by&&& Fung F. Lee &lee@umunhum.stanford.edu& and&&& Ricky Yeung& &Ricky.Yeung@& .
And Lee and Yeung refered to:&&& 1. "Zhong1guo2 yin1yang2 ri4yue4 dui4zhao4 wan4nian2li4"&by Lin2 Qi3yuan2. 《中国阴阳日月对照万年历》．林&&& 2. "Ming4li3 ge2xin1 zi3ping2 cui4yan2" by Xu2 Le4wu2.&《命理革新子平粹言》．徐&&& 3.& Da1zhong4 wan4nian2li4. 《大众万年历》
License:&&& GNU General Public License (GPL, see http://www.gnu.org).&&& In short, users are free to use and distribute this program&&& in whole. If users make revisions and distribute the revised&&& one, they are required to keep the revised source accessible&&& to the public.
Version:&&& 0.3.2,& Jan/16/2007, according to sprite's information, changed 3 codes:&&&&&&&&&&& a5d0 --& 0x0a5b0, d0 --& 0x052b0&&&&&&&&&&& d6a0 --& 0x056a0&&& 0.3.1,& Jan/15/2007, changed 1978's code from 0xb5a0 to 0xb6a0.&&&&&&&&&&& A young lady's birth day (lunar ) problem reported &&&&&&&&&&& on internet -- informed by sprite at linuxsir.org&&& 0.3.0,& Sep/25/2006, add coding line, prevent python to report warning&&& 0.2.0,& Jan/6/2002, ShengXiao(生肖), lunar leap month(闰月)&&&&&&&&&&& added.&&& 0.1.0,& Jan/4/2002
&--- Changsen Xu &&'''
#Remember, in this program:#&& month=0 means Januaray, month=1 means February ...;#&& day=0 means the first day of a month, day=1 means the second day,#&&&&&& so as to ease manipulation of Python lists. #&& year=0 is 1900, until the last step to output
daysInSolarMonth= [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]lunarMonthDays& = [29,30] # a short (long) lunar month has 29 (30) days */
shengXiaoEn&&&& = ["Mouse", "Ox", "Tiger", "Rabbit", "Dragon", "Snake",&&&&&&&&&&&&&&&&&& "Horse", "Goat", "Monkey", "Rooster", "Dog", "Pig"]shengXiaoGB&&&& = ["鼠", "牛", "虎", "兔", "龙", "蛇", "马", "羊", "猴", "鸡",&&&&&&&&&&&&&&&&&& "狗", "猪"]zhiGB&&&&&&&&&& = ["子", "丑", "寅", "卯", "辰", "巳", "午", "未", "申", "酉",&&&&&&&&&&&&&&&&&& "戌", "亥"]ganGB&&&&&&&&&& = ["甲", "乙", "丙", "丁", "戊", "己", "庚", "辛", "壬", "癸"]
monthEn&&&&&&&& = ['January', 'February', 'March', 'April', 'May', 'June',&&&&&&&&&&&&&&&&&& 'July', 'August', 'September', 'October', 'November',&&&&&&&&&&&&&&&&&& 'December']weekdayEn&&&&&& = ["Monday", "Tuesday", "Wednesday", "Thursday",&&&&&&&&&&&&&&&&&& "Friday", "Saturday", "Sunday"]weekdayGB&&&&&& = ["一", "二", "三", "四", "五", "六", "日"]numGB&&&&&&&&&& = ['○', "一", "二", "三", "四", "五", "六", "七", "八", "九",&&&&&&&&&&&&&&&&&& "十"]lunarHoliday&&& = {'0_0':'春节', '4_4':'端午', '7_14':'中秋', '8_8':'重阳',&&&&&&&&&&&&&&&&&& '0_14':'元宵'}
#&& encoding:#&&&&&& &b bbbbbbbbbbbb bbbb#&&&&& bit#&&& &1
0000#&&&&&&&&&&&&&& 6
3210#&& &&. ............ ....#&&&&& month#&& #&&&&&&&&&&&&&& M && L#&&&&&& &&&#&& b_j = 1 for long month, b_j = 0 for short month#&& L is the leap month of the year if 1&=L&=12; NO leap month if L = 0.#&& The leap month (if exists) is long one if M = 1.yearCode = [&&& &&&&&0x04bd8,&# 1900 &&& 0x04ae0, 0x0a570, 0x054d5, 0x0d260, 0x0d950,&# 1905 &&& 0x1a0, 0x09ad0, 0x055d2, 0x04ae0,&# 1910 &&& 0x0a5b6, 0x0a4d0, 0x0d250, 0x1d255, 0x0b540,&# 1915 &&& 0x056a0, 0x0ada2, 0x095b0, 0x170,&# 1920 &&& 0x0a4b0, 0x0b4b5, 0x06a50, 0x06d40, 0x1ab54,&# 1925 &&& 0x02b60, 0x0f2, 0x066,&# 1930 &&& 0x0d4a0, 0x0ea50, 0x06e95, 0x05ad0, 0x02b60,&# 1935 &&& 0x186e3, 0x092e0, 0x1c8d7, 0x0c950, 0x0d4a0,&# 1940 &&& 0x1d8a6, 0x0b550, 0x056a0, 0x1a5b4, 0x025d0,&# 1945 &&& 0x092d0, 0x0d2b2, 0x0a950, 0x0b557, 0x06ca0,&# 1950 &&& 0x0b550, 0x1da0, 0x0a5b0, 0x14573,&# 1955 &&& 0x052b0, 0x0a9a8, 0x0e950, 0x06aa0, 0x0aea6,&# 1960 &&& 0x0ab50, 0x04b60, 0x0aae4, 0x0a570, 0x05260,&# 1965 &&& 0x0f263, 0x0d950, 0x05b57, 0x056a0, 0x096d0,&# 1970 &&& 0x04dd5, 0x04ad0, 0x0a4d0, 0x0d4d4, 0x0d250,&# 1975 &&& 0x0d558, 0x0b540, 0x0b6a0, 0x195a6, 0x095b0,&# 1980 &&& 0x049b0, 0x0a974, 0x0a4b0, 0x0b27a, 0x06a50,&# 1985 &&& 0x06d40, 0x0af46, 0x0ab60, 0x0af5,&# 1990 &&& 0x0b0, 0x074a3, 0x0ea50, 0x06b58,&# 1995 &&& 0x055c0, 0x0ab60, 0x096d5, 0x092e0, 0x0c960,&# 2000 &&& 0x0d954, 0x0d4a0, 0x0da50, 0x0a0,&# 2005 &&& 0x0abb7, 0x025d0, 0x092d0, 0x0cab5, 0x0a950,&# 2010 &&& 0x0b4a0, 0x0baa4, 0x0ad50, 0x055d9, 0x04ba0,&# 2015 &&& 0x0a5b0, 0x1b0, 0x0a930, 0x07954,&# 2020 &&& 0x06aa0, 0x0ad50, 0x05b52, 0x04b60, 0x0a6e6,&# 2025 &&& 0x0a4e0, 0x0d260, 0x0ea65, 0x0d530, 0x05aa0,&# 2030 &&& 0x076a3, 0x096d0, 0x04bd7, 0x04ad0, 0x0a4d0,&# 2035 &&& 0x1d0b6, 0x0d250, 0x0d520, 0x0dd45, 0x0b5a0,&# 2040 &&& 0x056d0, 0x055b2, 0x049b0, 0x0a577, 0x0a4b0,&# 2045 &&& 0x0aa50, 0x1b255, 0x06d20, 0x0ada0&&&# 2049 ]yearsCoded = len(yearCode)
from sys import argv, exit, stdoutfrom time import time, localtimeow=stdout.write
class LunarYearInfo:&&& def __init__(self):&&&&&&& self.yearDays = 0&&&&&&& self.monthDays = [0]*13&&&&&&& self.leapMonth = -1& # -1 means no lunar leap month
yearInfo = [0]*yearsCoded #global variablefor i in range(yearsCoded):&&& yearInfo[i] = LunarYearInfo()
class Date:&&& def __init__(self, year, month, day, weekday=-1, gan=-1, zhi=-1):&&&&&&& self.year&& =year&&&&&&& self.month& =month&&&&&&& self.day&&& =day&&&&&&& self.weekday=weekday&&&&&&& self.gan&&& =gan&&&&&&& self.zhi&&& =zhi
solar1st = Date(0, 0, 30, weekday=2)&& #Wednesday, January 31, 1900lunar1st = Date(0, 0, 0,& weekday=2, gan=6, zhi=0)#Wednesday, First day, First month, 1900, 庚子年
def error(msg):&&& print 'Error:', exit(0)
def isSolarLeapYear (year):&&& year=year+1900&&& return (year%4 == 0) and (year%100 != 0) or (year%400 == 0)
baseYear=1201 - 1900# in fact, real baseYear=1201.& In order to ease calculation of# leap years. real baseYear must conform to:#&& realBaseYear%4==1 and realBaseYear%400==1.# Assert realBaseYear & solar1st.year .
# Compute the number of days from the Solar First Date# month=0 means January, ...def solarDaysFromBaseYear(d):&&& #d is a Date class&&& delta = d.year - baseYear &&& offset = delta*365 + delta/4 - delta/100 + delta/400&&& for i in range(d.month):&&& &offset += daysInSolarMonth[i];&&& if d.month&1 and isSolarLeapYear(d.year):&offset += 1&&& offset += d.day##&& print '___', year, month, day, 'offset=', offset ########&&& return offset
# Compute the number of days from the Solar First Date# month=0 means January, ..., year=0 means 1900, ...def solarDaysFromFirstDate (d): #d is a Date class&&& return solarDaysFromBaseYear (d) - solarDaysFromBaseYear (solar1st)
def calcLunarDaysPerMonth(iYear):&&& code = yearCode[iYear]&&& leapMonth = code&0xf #leapMonth==0 means no lunar leap month
&&& code &&= 4&&& for iMonth in range(12):&&&&&&& yearInfo[iYear].monthDays[11-iMonth] = lunarMonthDays [code&0x1]&&&&&&& code &&= 1
&&& if leapMonth&0:&&&&&&& yearInfo[iYear].leapMonth = leapMonth-1 &&&&&&& yearInfo[iYear].monthDays.insert (leapMonth,&&&&&&&&&&&&&&& lunarMonthDays [code & 0x1])&
def calcAllLunarYearsInfo():&&& for iYear in range(yearsCoded):&&&&&&& calcLunarDaysPerMonth (iYear)&&&&&&& for iMonth in range(13):&&&& yearInfo[iYear].yearDays += yearInfo[iYear].monthDays[iMonth]
#input dateSolar, return (dateLunar, isLunarMonthOrNot)def solar2Lunar(d): #d is a Date class&&& dLunar = Date(-1, -1, -1) #unknown lunar Date class
&&& offset = solarDaysFromFirstDate(d)
&&& dLunar.weekday& = (offset + solar1st.weekday)%7
&&& for iYear in range(yearsCoded):&&&&&&& if offset & yearInfo[iYear].yearDays:&&&&&&&&&&& dLunar.year = iY break&offset -= yearInfo[iYear].yearDays&&& if dLunar.year == -1:&& error ("Date out of range.")
&&& dLunar.gan&&&&& = (dLunar.year + lunar1st.gan) % 10&&& dLunar.zhi&&&&& = (dLunar.year + lunar1st.zhi) % 12
&&& for iMonth in range(13):&&&&&&& if offset& yearInfo[dLunar.year].monthDays[iMonth]:&&&&&&&&&&& dLunar.month = iM break&offset -= yearInfo[dLunar.year].monthDays[iMonth]
&&& dLunar.day = offset&&& isLeapMonth=0&&& if yearInfo[dLunar.year].leapMonth &=0:&&&&&&& if dLunar.month ==& yearInfo[iYear].leapMonth + 1:&&&&&&&&&&& isLeapMonth=1&&&&&&& if dLunar.month & yearInfo[dLunar.year].leapMonth:&&&&&&&&&&& dLunar.month -= 1
&&& return (dLunar, isLeapMonth)
def getSolarDaysInMonth (year, month):&&& if isSolarLeapYear(year) and month==1:&&&&&&&&&&& return 29&&& else:&& return daysInSolarMonth[month]
def num2GB (num):&&& if num==10:&&&&&&& return '十'&&& elif num&10 and num&20:&&&&&&& return '十' + numGB[num-10]
&&& tmp=''&&& while num&10:&&&&&&& tmp = numGB[num%10] + tmp&&&&&&& num = int(num/10)&&& tmp = numGB[num] + tmp&&& return tmp
def lunarDate2GB (dLunar, isLeapMonth):&&& tmp = str(dLunar.month)+'_'+str(dLunar.day)&&& if lunarHoliday.has_key( tmp ):&&&&&&& return '%s& '% lunarHoliday[tmp] + \&&&&&&&&&&&&&& ' '*(6-len(lunarHoliday[tmp]))&&& elif dLunar.day==0:&&& &&&&&&& tmp2 = '闰'*isLeapMonth + num2GB(dLunar.month+1) +'月'&&&&&&& return '%s' % tmp2 + ' '*(8-len(tmp2))&&& elif dLunar.day&10:&&&&&&& return '初' + num2GB(dLunar.day+1)&&& else:&&&&&&& return num2GB(dLunar.day+1)
def outputCalendar(year, month):&&& dLunar = Date(-1,-1,-1)&&& ow ('\n&&&& 阳历%d年%d月&&&&&&&& ' % (year+1900, month+1) )
&&& for iDay in range( getSolarDaysInMonth(year, month) ):&&&&&&& dSolar = Date(year, month, iDay)&&&&&&& dLunar, isLeapMonth = solar2Lunar (dSolar)
&&&&&&& if iDay==0:&&&&&&&&&&& ow ('始于 阴历%s年%s%s月 (%s%s年, 生肖属%s)\n' %&&&&&&&&&&&&&&& ( num2GB(dLunar.year+1900), '闰'*isLeapMonth,&&&&&&&&&&&&&&&&& num2GB(dLunar.month+1),&&&&&&&&&&&&&&&&& ganGB [dLunar.gan], zhiGB[dLunar.zhi], shengXiaoGB[dLunar.zhi]&&&&&&&&&&&&&&& ))&&&&&&&&&&& ow ('='*74 + '\n')&&&&&&&&&&& for i in range(7):&&&&&&&&&&&&&&& ow ("%3s %2s&&&& " % (weekdayEn[i][:3], weekdayGB[i]) )&&&&&&&&&&& ow('\n\n')&&&&&&&&&&& for i in range(dLunar.weekday): ow(' '*11)
&&&&&&& elif dLunar.weekday==0: ow('\n')
&&&&&&& ow ( "%2d %-8s" %(iDay+1, lunarDate2GB(dLunar, isLeapMonth) ) )&&& ow('\n\n')
def checkArgv (argv):&&& argc = len(argv)&&& if argc==1 or argv[1] in ('-h', '--help'):&&&&&&& print __doc__; exit(0)
&&& #in case people input arguments as "4-digit-year month"&&& if argc==3 and len(argv[1]) == 4 and len(argv[2]) in (1,2):&&&&&&& argv[1], argv[2] = argv[2], argv[1]
&&& &&& #Get month&&& month=-1&&& for iMonth in range(12):&&&&&&& if argv[1].lower() == monthEn[iMonth].lower() or \&&&&&&&&&& argv[1].lower() == monthEn[iMonth][:3].lower():&&&&&&&&&&&&&& month = iMonth+1; break&&& if month==-1:&&&&&&& month = eval(argv[1])
&&& if month&1 or month&12:&&&& error ("Month not within 1--12.")
&&& #Get year&&& if argc==2: year = localtime(time())[0]&&& else:&&&&&&& if len(argv[2]) != 4:&& error ("Year must be 4 digits.")&&&&&&& year = eval(argv[2])&&&&&&& if year&1900 or year&= 1900+yearsCoded or (year==1900 and month==1):&&&&&&&&&&& error ("Year must be within %d--%d, excluding 1900/1."&&&&&&&&&&&&&&&&&&& % ( + yearsCoded-1) )
&&& return year-1900, month-1
year, month = checkArgv(argv)calcAllLunarYearsInfo()outputCalendar(year, month)
这个也有问题（1989年8月的数据转换成农历就有问题）
看了好几个程序，发现实现这个并不需要什么NB的算法（好像也不存在这样的算法）可以直接实现阳历转为阴历的，都是记录了一堆阴历的数据，然后根据和基本时间来算相差几天来计算的，所有阴历数据的正确性决定了这个程序的正确性。
同学给了一个lua的程序，我试了一下，还没有找到错误的，先直接给上程序（直接从lua转成python的，写的比较乱）
代码如下:#!/usr/bin/env python# -*- coding: utf-8 -*-import math
def GetDayOf(st):&&& #–天干名称&&& cTianGan = ["甲","乙","丙","丁","戊","己","庚","辛","壬","癸"]&&& #–地支名称&&& cDiZhi = ["子","丑","寅","卯","辰","巳","午", "未","申","酉","戌","亥"]&&& #–属相名称&&& cShuXiang = ["鼠","牛","虎","兔","龙","蛇", "马","羊","猴","鸡","狗","猪"]&&& #–农历日期名&&& cDayName =[&&&&&&& "*","初一","初二","初三","初四","初五",&&&&&&& "初六","初七","初八","初九","初十",&&&&&&& "十一","十二","十三","十四","十五",&&&&&&& "十六","十七","十八","十九","二十",&&&&&&& "廿一","廿二","廿三","廿四","廿五",&&&&&&& "廿六","廿七","廿八","廿九","三十"&&& ]&&& #–农历月份名&&& cMonName = ["*","正","二","三","四","五","六", "七","八","九","十","十一","腊"]
&&& #–公历每月前面的天数&&& wMonthAdd = [0,31,59,90,120,151,181,212,243,273,304,334]&&& #– 农历数据&&& wNongliData = [,1,5,396438&&& ,4,0,1,3402&&& ,1,,605,,,1738&&& ,,06,398762&&& ,18,7,6,2413&&& ,7,,,&&& ,,,91,330031&&& ,42,0,3222&&& ,2,,,605,,2709&&& ,,,07,265877]
&&& #—取当前公历年、月、日—&&& wCurYear = st["year"]&&& wCurMonth = st["mon"]&&& wCurDay = st["day"]&&& #—计算到初始时间日的天数：(正月初一)—&&& #nTheDate = (wCurYear – 1921) * 365 + (wCurYear – 1921)/4 + wCurDay + wMonthAdd[wCurMonth] – 38&&& nTheDate = (wCurYear – 1921) * 365 + (wCurYear – 1921)/4 + wCurDay + wMonthAdd[wCurMonth-1] – 38&&& if (((wCurYear % 4) == 0) and (wCurMonth & 2)):&&&&&&& nTheDate = nTheDate + 1
&&& #–计算农历天干、地支、月、日—&&& nIsEnd = 0&&& m = 0&&& while nIsEnd != 1:&&&&&&& #if wNongliData[m+1] & 4095:&&&&&&& if wNongliData[m] & 4095:&&&&&&&&&&& k = 11&&&&&&& else:&&&&&&&&&&& k = 12&&&&&&& n = k&&&&&&& while n&=0:&&&&&&&&&&& nBit = wNongliData[m]&&&&&&&&&&& for i in range(n):&&&&&&&&&&&&&&& nBit = math.floor(nBit/2);
&&&&&&&&&&& nBit = nBit % 2
&&&&&&&&&&& if nTheDate &= (29 + nBit):&&&&&&&&&&&&&&& nIsEnd = 1&&&&&&&&&&&&&&& break
&&&&&&&&&&& nTheDate = nTheDate – 29 – nBit&&&&&&&&&&& n = n – 1
&&&&&&& if nIsEnd != 0:&&&&&&&&&&& break&&&&&&& m = m + 1
&&& wCurYear = 1921 + m&&& wCurMonth = k – n + 1&&& wCurDay = int(math.floor(nTheDate))&&& if k == 12:&&&&&&& if wCurMonth == wNongliData[m] / 65536 + 1:&&&&&&&&&&& wCurMonth = 1 – wCurMonth&&&&&&& elif wCurMonth & wNongliData[m] / 65536 + 1:&&&&&&&&&&& wCurMonth = wCurMonth – 1
&&& print '阳历', st["year"], st["mon"], st["day"]&&& print '农历', wCurYear, wCurMonth, wCurDay&&& #–生成农历天干、地支、属相 ==& wNongli–&&& szShuXiang = cShuXiang[(((wCurYear - 4) % 60) % 12) + 1]&&& szShuXiang = cShuXiang[(((wCurYear - 4) % 60) % 12) + 1]&&& zNongli = szShuXiang + '(' + cTianGan[(((wCurYear - 4) % 60) % 10)] + cDiZhi[(((wCurYear - 4) % 60) % 12)] + ')年'&&& #–szNongli,"%s(%s%s)年",szShuXiang,cTianGan[((wCurYear - 4) % 60) % 10],cDiZhi[((wCurYear - 4) % 60) % 12]);
&&& #–生成农历月、日 ==& wNongliDay–*/&&& if wCurMonth & 1:&&&&&&& szNongliDay =& "闰" + cMonName[(-1 * wCurMonth)]&&& else:&&&&&&& szNongliDay = cMonName[wCurMonth]
&&& szNongliDay =& szNongliDay + "月" + cDayName[wCurDay]&&& print szNongliDay&&& #return szNongli .. szNongliDay
def main():&&& st = {"year": 1989, "mon": 8, "day": 1}&&& GetDayOf(st)&&& st1 = {"year": 2013, "mon": 10, "day": 7}&&& GetDayOf(st1)&&& st1 = {"year": 2013, "mon": 10, "day": 1}&&& GetDayOf(st1)&&& #print("" .. GetDayOf(st))main()
数据基本上正确了，根据自己的需要改一改程序就可以了。以后有时间在改好一点的。
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问题1：公历日是农历几月几号？
答案1：农历号（二零一六丙申年七月廿二日），生肖属猴
问题2：阴历日是阳历几月几号？农历日是公历几号？
答案2：公历/阳历号（猴年），星期3
问题3：公历日星座是什么？农历日是什么星座？
答案3：公历号是【处女座】
问题4：公历2016年8月有几天？2016年阳历8月份有多少天？
答案4：31天
问题5：公历日出生生肖属相是什么？
答案5：公历号出生的人生肖属猴。
问题6：公历日是什么命？2016年农历7月22日出生什么命？
答案6：公历号出生的人年命纳音为【山下火】，我们俗称【火命】。
问题7：公历号是什么日子？2016年阴历7月22日什么日子？
答案7：阳历号的六十甲子纪年（年柱月柱日柱）：丙申年，丙申月，戊寅日，出生年月日五行：火金 火金 土木，纳音五行：山下火 山下火 城墙土
阴阳历查询表，公历农历对照表，农历阳历对照表公历日是农历多少号，阴历号是阳历多少号，号是什么日子，农历戊辰年六月廿四日
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1988<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="<option value="年
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公历日是什么日子
1988年8月阴历阳历对照表，1988年8月公历农历查询表
阴历阳历查询表，阴历阳历对照表，农历阳历对照表
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其他1条回答
好！公历是日，再点击公历生日就会显示是几月几日了，再输入年月日。你可以用QQ里的个人资料设置为农历生日
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